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Standard enthalpy of formation of ${SO}_{2}$ is –X kJ/mole. Enthalpy of combustion of Rhombic sulphur is……..kJ.

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–X/8

-4X

-8X

–X

answer is D.

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Detailed Solution

$\frac{1}{8} S_{8} (α) + O_{2} (g) \to S O_{2} (g), Δ H = - X$

$S_{8} (α) + 8 O_{2} (g) \to 8 S O_{2} (g), Δ H = - 8 X$

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