Standard entropy of X2,Y2 and X2Y3 are 60. 40 and 150 in J/KmolX2+32Y2⟶X2Y3;ΔH=+30kJThe temperature at which reaction will attain equilibrium is:

ΔSreaction =150−32×40−60=30T=30×10830K

Standard entropy of X2,Y2 and X2Y3 are 60. 40 and 150 in J/KmolX2+32Y2⟶X2Y3;ΔH=+30kJThe temperature at which reaction will attain equilibrium is:

ΔSreaction =150−32×40−60=30T=30×10830K

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Standard entropy of $X_{2}, Y_{2}$ and $X_{2} Y_{3}$ are 60. 40 and $150 in J / Kmol$
$X_{2} + \frac{3}{2} Y_{2} ⟶ X_{2} Y_{3}; Δ H = + 30 kJ$
The temperature at which reaction will attain equilibrium is:

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$\begin{array}{l} Δ S_{reaction} = 150 - \frac{3}{2} \times 40 - 60 = 30 \\ T = \frac{30 \times 10^{8}}{30} K \end{array}$

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Standard entropy of X2,Y2 and X2Y3 are 60. 40 and 150 in J/KmolX2+32Y2⟶X2Y3;ΔH=+30kJThe temperature at which reaction will attain equilibrium is:

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Standard entropy of $X_{2}, Y_{2}$ and $X_{2} Y_{3}$ are 60. 40 and $150 in J / Kmol$
$X_{2} + \frac{3}{2} Y_{2} ⟶ X_{2} Y_{3}; Δ H = + 30 kJ$
The temperature at which reaction will attain equilibrium is: