Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is

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10 Hz

2 Hz

4 Hz

5 Hz

answer is C.

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Detailed Solution

String vibrates in five segment so $\frac{5}{2} λ = l \Rightarrow λ = \frac{2 l}{5}$
Hence $n = \frac{v}{λ} = 5 \times \frac{v}{2 l} = 5 \times \frac{20}{2 \times 10} = 5 Hz$

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