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Standing waves are produced in a $10 m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 m / s$ , the frequency is

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$5 H z$

$2 H z$

$4 H z$

$10 H z$

answer is C.

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Detailed Solution

$5 \frac{λ}{2} = 10$ , Therefore $λ = 4 m$ .

Now $f = \frac{v}{λ} = \frac{20}{4} = 5 H z$

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