Starting from rest, a particle rotates in a circle of radius R=2m With an angular acceleration of π4rads-2 . The magnitude of average velocity of the particle over the time it rotates one quarter of circle is

θ=12α=12π4t2⇒t=2sV→avg=S→Δt=2R2=1ms−1

Starting from rest, a particle rotates in a circle of radius R=2m With an angular acceleration of π4rads-2 . The magnitude of average velocity of the particle over the time it rotates one quarter of circle is

θ=12α=12π4t2⇒t=2sV→avg=S→Δt=2R2=1ms−1

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Starting from rest, a particle rotates in a circle of radius $R = \sqrt{2} m$ With an angular acceleration of $\frac{π}{4} {rads}^{- 2}$ . The magnitude of average velocity of the particle over the time it rotates one quarter of circle is

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$1.25 {ms}^{- 1}$

$2 {ms}^{- 1}$

$1.5 {ms}^{- 1}$

$1 {ms}^{- 1}$

answer is C.

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$θ = \frac{1}{2} α = \frac{1}{2} \frac{π}{4} t^{2} \Rightarrow t = 2 s$

$|{\vec{V}}_{a v g}| = \frac{|\vec{S}|}{Δ t} = \frac{\sqrt{2} R}{2} = 1 m s^{- 1}$

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Starting from rest, a particle rotates in a circle of radius R=2m With an angular acceleration of π4rads-2 . The magnitude of average velocity of the particle over the time it rotates one quarter of circle is

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Starting from rest, a particle rotates in a circle of radius $R = \sqrt{2} m$ With an angular acceleration of $\frac{π}{4} {rads}^{- 2}$ . The magnitude of average velocity of the particle over the time it rotates one quarter of circle is