Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Starting from rest, the time taken by a body sliding down on a rough inclined plane at 450 with the horizontal is twice the time taken to travel on a smooth plane of the same inclination and same distance. Then, the coefficient of kinetic friction is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

0.75

b

0.25

c

0.50

d

0.33

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Coefficient of kinetic friction, μ=tanθ[11/n2]

here θ=450 and n=2

μ=tan 450[11/22]=1¼ =3/4=0.75

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon