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Q.

State if the following is true or false.


P  and Q are the mid-points of the sides CAand CB respectively of ΔABC   right angled at C.  then 4 AQ 2 + BP 2 =5 AB 2  .


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a

True

b

False 

answer is A.

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Detailed Solution

We need to check whether  4 AQ 2 + BP 2 =5 AB 2   holds good or not.
Consider the figure,
Question ImageHere, ABC is the triangle and P and Q are the points on the line’s AC and BC respectively.
In triangle ACB,
c= 90 °  
AB2=AC2+BC2........(1)
Now apply the Pythagoras theorem in ACQ,
  A Q 2 =A C 2 +Q C 2 A Q 2 =A C 2 + BC 2 2 A Q 2 =A C 2 + BC 4 2 4A Q 2 =4A C 2 +B C 2 .......(2)            Using Pythagoras theorem in ΔPCB  ,
P B 2 =P C 2 +B C 2 P B 2 = A C 2 4 +B C 2 4P B 2 =A C 2 +4B C 2 ....(3)                Add equation (2) and (3),
4A Q 2 +4P B 2 =4A C 2 +B C 2 +A C 2 +4B C 2   4 A Q 2 +P B 2 =5 A C 2 +B C 2   Substitute the value for A C 2 +B C 2   by using equation (i),
  4 A Q 2 +P B 2 =5 A B 2  
The identity 4 A Q 2 +P B 2 =5 A B 2   holds good.
Therefore, the statement is true.
Hence, option 1 is correct.
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