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Q.
State if the statement is true or false: The representation of and on the real number line is
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a
True
b
False
answer is A.
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Detailed Solution
We have to find if the given representation of
and
is true or not.
To represent and on the number line, we have to represent first.
To do so, mark a point 2 units away from the starting point, i.e., 0, and then draw a perpendicular on that line, of 1 unit.
Next, join the initial point with the free end of the perpendicular to form a triangle as shown below.
Applying Pythagoras theorem on the above triangle, we get the length of the hypotenuse as follows,
Now, taking the hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
Next, to represent on the number line, repeat the same procedure as for , i.e., on the same triangle, considering the hypotenuse as the base, draw a perpendicular line of 1 unit and join it to the initial point as shown below.
Applying the Pythagoras theorem on the second triangle, we get,
Now, taking the second hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
Again, for representing , again, repeat the same procedure as for , i.e., on the second triangle, considering the hypotenuse as the base, draw a perpendicular line of 1 unit and join it to the initial point as shown below.
Applying the Pythagoras theorem on the third triangle, we get,
Now, taking the third hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
In this way, and can be represented on a real number line and so, the given representation is correct.
Hence, the statement is true.
So, the correct option is 1.
To represent and on the number line, we have to represent first.
To do so, mark a point 2 units away from the starting point, i.e., 0, and then draw a perpendicular on that line, of 1 unit.
Next, join the initial point with the free end of the perpendicular to form a triangle as shown below.
Now, taking the hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
Next, to represent on the number line, repeat the same procedure as for , i.e., on the same triangle, considering the hypotenuse as the base, draw a perpendicular line of 1 unit and join it to the initial point as shown below.
Now, taking the second hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
Again, for representing , again, repeat the same procedure as for , i.e., on the second triangle, considering the hypotenuse as the base, draw a perpendicular line of 1 unit and join it to the initial point as shown below.
Now, taking the third hypotenuse as the radius and the initial point as the center, draw an arc that intersects the number line. The point where it intersects is , as shown above in the diagram.
In this way, and can be represented on a real number line and so, the given representation is correct.
Hence, the statement is true.
So, the correct option is 1.
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