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Q.

State True/ False:


The daily expenditure of 100 families is given below. If the mean daily expenditure is Rs.57.6 and the sum of frequency is 50, then, f 1  and  f 2  are respectively 8 and 10.


Class

0-20

20-40

40-60

60-80

80-100

100-120

Frequency

7

f1

12

f2

8

5


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a

True

b

False  

answer is A.

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Detailed Solution

Consider the given table about the daily expenditure of 100 families,

Class

0-20

20-40

40-60

60-80

80-100

100-120

Frequency

7

f1

12

f2

8

5

It is given that the sum of frequencies is 50.
7+ f 1 +12+ f 2 +8+5=50 f 2 =18 f 1 (1)   The frequency distribution table for the given data is:

Class interval

Frequency

fi

Mid-value

xi

fixi

0-20

7

10

70

20-40

f1

30

30f1

40-60

12

50

600

60-80

f2=18-f1

70

1260-70f1

80-100

8

90

720

100-120

5

110

550

 

50

 

3200-40f1

We know that mean (x̲) = fixifi.
Here,  fixi=3200-40f1, fi=50 and Mean (x̲) = 57.6.
Therefore,
57.6= 320040 f 1 50 2880=320040 f 1 40 f 1 =320 f 1 =8   Substituting the value of f 1   in equation (1):
f 2 =188 f 2 =10  
Hence, the value of f 1   and f 2  are 8 and 10 respectively.
Thus, the given statement is true.
Therefore, option 1 is correct.
 
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