Q.

State True/ False:


The factors of 3 (a2b) 2 5(a2b)  is (a-2b)(3a-6b-5).


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a

True

b

False  

answer is A.

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Detailed Solution

The given expression is:
3 a2b 2 5 a2b   Write prime factors of each term:
3 a2b 2 =3× a2b × a2b 5 a2b =5× a2b  
HCF 3 a2b 2 ,5 a2b = a2b  
Taking HCF common,
3 a2b 2 5 a2b a2b 3 a2b 5 a2b 3a6b5  
Hence, factors of 3 a2b 2 5 a2b = a2b 3a6b5  .
Thus, the given statement is true.
Therefore, option 1 is correct.
 
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