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Q.

State True/ False:


The table below shows the daily expenditure on food of 30 households in a locality. Then the median of daily expenditure on food is Rs.208.2.


DAILY EXPENDITURE (in Rs.)

NUMBER OF HOUSEHOLDS

100-150

6

150-200

7

200-250

12

250-300

3

300-350

2


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a

True

b

False 

answer is B.

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Detailed Solution

Consider the given table,

DAILY EXPENDITURE (in Rs.)

NUMBER OF HOUSEHOLDS

100-150

6

150-200

7

200-250

12

250-300

3

300-350

2

The frequency distribution table for the given data is:

C.I.

fi

c.f.

100-150

6

6

150-200

7

13

200-250

12

25

250-300

3

28

300-350

2

30

 

fi=30

 

Here, we have,
N= fi = 30
N2=302 = 15
We can observe that the cumulative frequency just greater than 15 is 25 and the corresponding class is 200250   .
Therefore, the median class is 200250  .
We know that, the formula for median is,
  M=l+ h× N 2 cf f  , where, l=   the lower limit of the median class, N= frequency   , and cf=   cumulative frequency of the class just preceding the median class.
Note that, here
l= 200
N= 30
f=12
h=50
c.f= 13 
Therefore, the median is,
=200+ 50× 1513 12 =200+8.33 =208.33  
Hence, the median of daily expenditure on food is Rs.208.33.
Thus, the given statement is false.
Therefore, option 2 is correct.
 
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