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State true or false.

Apoorv throws $2$ dice once and computes the product of the numbers appearing on the dice. Peehu throws $1$ die and squares the number that appears on it. Apoorv has the better chance of getting the number $36$ .

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True

False

answer is B.

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Detailed Solution

It is given that, Apoorv throws

2

dice once and computes the product of the numbers appearing on the dice.
The number of possible for the product to be

36

1

and the number of total outcomes for

2

dice is

36

.
Let

A

be the event of the product to be

36

, then the probability of the event can be calculated by,

P (A) = N u m b e r of favourable outcomes T o t a l number of outcomes

= 136

So probability for the dice thrown by Apoorv is

136

.
Peehu throws

1

die and square the number that appears on it.
The number of possible outcomes for the square of the number is 36 is 1, and the number of possible outcomes for one dice is

6

.
So the probability for the dice thrown by Peehu is

16 = 636

.
Hence

636 > 136

.
Hence the correct statement is that Peehu has the better chance of getting the number

36

.
Hence the statement is false.
Therefore, option 2 is correct.

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