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Q.

State true or false.


In the given figure, O   is the center of the circle and XOY   is a diameter. If XZ   is any other chord of the circle, then XY>XZ  .


Question Image

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a

True

b

False 

answer is A.

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Detailed Solution

It is given that O   is the center of the circle and XOY   is a diameter.
XZ   is any other chord of the circle.
We have to show that, XY>XZ  .
Consider the figure given below-
Question ImageConsider ΔXOZ  .
Since, the sum of any 2   sides in a triangle is greater than its third side.
OX+OZ>XZ                                       ……(1)
The radius of the circle,
OZ=OY                                                ......(2)
Diameter of the circle,
OX+OY=XY                                    ......(3)
Consider ΔXOZ   and equation (1).
OX+OZ > XZ   OX+OY>XZ   from equation (2),
Therefore, XY>XZ   from equation (3).
If O   is the center of the circle and XOY   is a diameter. If XZ   is any other chord of the circle, then XY>XZ  .
Hence the statement is true.
Hence option 1 is correct.
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