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Q.

State true or false.


The mean of the following frequency distribution using step deviation method is 55.5.


Marks

0-15

15-30

30-45

45-60

60-75

75-90

No. of students

2

4

5

20

9

10


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a

True

b

False 

answer is A.

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Detailed Solution

Given:

Marks

0-15

15-30

30-45

45-60

60-75

75-90

No. of students

2

4

5

20

9

10

Formula:
Mean using step deviation method:
 Mean =A+ h× f i u i f i  where,  u i = x i A h   ,   A   is the assumed mean, f   is the frequency and h  is the size of the class of the given data.
We have to find mean marks. The frequency distribution table will be:

Class interval

Frequency, fi

Mid-value, xi

ui=xi-Ah=xi-29.510

fiui

0-15

2

7.5

-3

-6

15-30

4

22.5

-2

-8

30-45

5

37.5

-1

-5

45-60

20

52.5=A

0

0

60-75

9

67.5

1

9

75-90

10

82.5

2

9

 

Σfi=50

 

 

Σfiui=10

We have to find the mean marks.
Observing from the above table:
A=52.5,h=15, f i =50, and  f i u i =10  
 Applying formula:
   Mean  =52.5+ 15× 10 50 =52.5+3 =55.5  
The mean marks are 55.5.
Thus, the given statement is true.
Therefore, the correct option is 1.
 
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