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Q.

State true or false.


The solutions of algebraic expressions a(x+y) +b(x-y) =a2-ab+b2 and a(x+y) -b(x-y) =a2+ab+b2 would be Question Image and Question Image.


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a

True

b

False 

answer is A.

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Detailed Solution

The given statement is true.
Concept- We shall use the elimination method to answer this question. We will be able to solve the problem further if we use the elimination approach to eliminate one of the terms with the variable. Because there are algebraic equations, we shall utilize elimination with caution.
We will consider Question Image and
Question Image.
We shall now employ the elimination process. We will delete the phrase using this wayQuestion Image by combining equations I and (ii) . As a result, we have
Question ImageQuestion ImageAs a result,
Question ImageQuestion ImageQuestion ImageWe'll use 'a' as a common term from the left side of the equation now. As a result, we have a new equationQuestion Image which can also be written as Question Image.
Now we will eliminate the term Question Image by subtracting the equations (i) and (ii) . Therefore we have
Question ImageQuestion ImageAs a result,
Question ImageQuestion ImageQuestion ImageWe shall now consider the term 'b' to be a common term from the left side of the equation. As a result, we receive Question Image which after solving can be written as Question Image or we have Question ImageWe will use the elimination approach again on equations (iii) and (iv) to eliminate the variable y. As a result, we shall combine equations (iii) and (iv) . As a result, we receive
Question ImageQuestion ImageQuestion ImageAs a result, we now have a new equation, which is as followsQuestion Image or Question Image.
In this stage, we will apply substitution. That is we will substitute the value of Question Image given as Question Image in equation (iv) .
As a result, we receive
Question ImageQuestion ImageQuestion ImageQuestion ImageTherefore, the value of Question Image.
So, the required values of Question Image and Question Image.
Hence, the answer is option 1.
 
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