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Q.

State true or false:


Both the roots of the equation  xa xb + xb xc + xc xa =0  are real but they are equal only when a=b=c.


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a

True

b

False 

answer is A.

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Detailed Solution

Given equation is (xa)(xb)+(xb)(xc)+(xc)(xa)=0  
Now,
Question ImageCompare given equation with general form, a x 2 +bx+c=0  
a =3 b =2(a+b+c) c =ab+bc+ca  
Assume D be the discriminant of quadratic equation.
So,
D= (2(a+b+c)) 2 4×3×(ab+bc+ca) D=4 (a+b+c) 2 12(ab+bc+ca) D=4 a 2 + b 2 + c 2 +2ab+2bc+2ca 12ab12bc12ca D= (4 a 2 +4 b 2 +4 c 2 +8ab+8bc+8ca 12ab12bc12ca  
Question ImageThe square of any number is always a positive number.
From the discriminant it is clear that 2 is a positive number and (ab) 2 , (bc) 2  and (ac) 2   are greater than zero, so the product of a positive number and positive number is always a positive number it means the number is strictly greater than zero when abc   .
As the discriminant is strictly greater than zero, so the roots of given quadratic equation are real. When a=b=c   the discriminant becomes 0, so the roots are equal when a=b=c  
Therefore, it is true that the roots of the equation xa xb + xb xc + xc xa =0   are real but they are equal only when a=b=c  .
Hence, the correct option is 1.
 
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