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Q.

State true or false:

If a and b are two odd positive integers such that a > b, then one of the two numbers (a+b)2 and (a-b)2 is odd and the other is even.

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a

True

b

False 

answer is A.

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Detailed Solution

We have to check whether one of the two numbers (a+b)2 and (a-b)2 is odd and the other is even, if a and b are two odd positive integers such that a > b.
Let the two consecutive odd positive integers be 4q+1 and 4q+3 where q is a whole number.
As, a>b, a=4q+3 and b=4q+1.
Hence,
(a+b)2=4q+3+4q+12 (a+b)2=8q+42 (a+b)2=2(2q+1) Hence, 2(2q+1) represents an even number as it is completely divisible by 2.
(a-b)2=4q+3-4q+12 (a-b)2=22 (a-b)2=1 Hence, 1 is an odd number.
Therefore, it is true that if a and b are two odd positive integers such that a > b, then one of the two numbers (a+b)2 and (a-b)2 is odd and the other is even.
Hence, option 1 is correct.
 
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