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State true or false:
The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is 4663.

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True

False

answer is A.

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Detailed Solution

Given numbers are 520 and 468.

2 520, 468 2 260, 234 2 130, 117 3 65, 117 3 65, 39 5 65, 13 13 13, 13 1,1

LCM = 2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 13

\Rightarrow LCM = 4680

\Rightarrow

The number divisible by 520 and 468

= 4680

Number when increased by 17 is divisible by 520 and 468

= LCM - 17

\Rightarrow 4680 - 17

\Rightarrow 4663

Therefore, it is true that a number which when increased by 17 is divisible by 520 and 468 is 4663.
Hence, option 1 is correct.

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