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Q.

State true or false:

The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is 4663.

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a

True

b

False 

answer is A.

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Detailed Solution

Given numbers are 520 and 468.
  2 520,468   2 260,234   2 130,117   3 65,117   3 65,39   5 65,13  13 13,13     1,1  
LCM=2×2×2×3×3×5×13 ⇒LCM=4680 ⇒ The number divisible by 520 and 468 =4680
Number when increased by 17 is divisible by 520 and 468 =LCM-17
⇒ 4680-17 ⇒ 4663 Therefore, it is true that a number which when increased by 17 is divisible by 520 and 468 is 4663.
Hence, option 1 is correct.
 
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State true or false:The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is 4663.