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Q.

State true or false:

The square of any positive integer is of the form 5q, 5q+1 and 5q+4 for some integer q.

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a

True

b

False 

answer is A.

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Detailed Solution

We have to check whether the square of any positive integer is of the form 5q, 5q+1 and 5q+4 for some integer q.
Euclid's Division Lemma states that, if two positive integers “a” and “b”, then there exists unique integers “q” and “r” such that which satisfies the condition:
a=bq+r where 0rb
Consider ‘n’ as a positive integer for some integer q.
n=bq+r From Euclid's Division Lemma for b = 5,
n=5k+r where 0r5   …... (1)
Substitute r=0 (1) and square on both sides,
n2=5k2 n2=5(5k2) Let 5k2 be ‘q’, then n2=5q.
Here, q is some integer.
Substitute r=1 in (1) and square on both sides,
n2=5k+12 n2=25k2+10k+1 n2=5(5k2+2k)+1 Let 5k2+2k be ‘q’, then n2=5q+1.
Here, q is some integer.
Substitute r=2 in (1) and square on both sides,
n2=(5k+3)2 n2=25k2+20k+4 n2=5(5k2+4k)+4 Let (5k2+4k) be ‘q’.
n2=5q+4 Here, q is some integer.
Substitute r=3 in (1) and square on both sides,
n2=(5k+3)2 n2=25k2+30k+9 n2=5(5k2+6k+1)+4 Let (5k2+6k+1) be ‘q’.
n2=5q+4 Here, q is some integer.
Substitute r=4 in (1) and square on both sides,
n2=(5k+4)2 n2=25k2+40k+16 n2=5(5k2+8k+3)+1 Let (5k2+8k+3) be ‘q’.
n2=5q+1 Here, q is some integer.
Therefore, it is true that the square of any positive integer is of the form 5q, 5q+1 and 5q+4 for some integer q.
Hence, option 1 is correct.
 
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