State whether the following statement is true or false.

a – [2b – {3a – (2b – 3c)}] = 4a – 4b + 3c.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

True

False

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We have to solve the above equation, and to solve these type of equations, we have to separate with the symbols ( ) first, then { } and then [ ].
a – [2b – {3a – (2b – 3c)}] = a – [2b – {3a – 2b + 3c}] = a – [2b – 3a + 2b – 3c] = a – [4b – 3a – 3c] = a – 4b + 3a + 3c = 4a – 4b + 3c
Hence, LHS = RHS.
Therefore, the given equality is true.
So, the correct option is 1.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th