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Q.

State whether the following statement is true or false.


One of any three consecutive positive integers must be divisible by 3.


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a

True

b

False 

answer is A.

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Detailed Solution

According to Euclid’s division lemma, we know,
Given positive integers say a and b, there exist unique integers q and r which satisfies a=bq+r, where 0r<b.
Let q be the quotient and r be the remainder when n is divided by 3.
Following that, it is expressed as, using Euclid's division algorithm.
n=3q+r, where 0r<3  
Therefore, there exist three cases,
If r=0, then n=3q.
Which means n is divisible by 3.
Adding 1 on both sides,
n+1=3q+1  
This means n+1 is not divisible by 3.
After adding 2 on both sides, we get,
n+2=3q+2  
This means n+2 is not divisible by 3.
Consequently, only n, in this case, is divisible by 3.
For r=1
n=3q+1
which is not divisible by 3.
Adding 1 on both sides,
n+1=3q+1+1 n+1=3q+2  
This means n+1 is not divisible by 3.
Now, we will add 2 on both sides.
n=3q+1 n+2=3q+1+2 n+2=3q+3 n+2=3 q+1  
 Hence, n+2 is divisible by 3.
Hence, in this case, only n+2 is divisible by 3.
For r=2, n=3q+2, which is not divisible by 3.
Adding 1 on both sides,
n+1=3q+2+1 n+1=3q+3 n+1=3 q+1  
Hence, n+1 is divisible by 3.
Now, we will add 2 on both sides.
n+2=3q+2+2 n+2=3q+4 n+2=3q+3+1 n+2=3 q+1 +1  
Hence, n+2 is not divisible by 3.
Hence, in this case, only n+1 is divisible by 3.
Thus, it is proved that one of n,n+1   and n+2   is divisible by 3.
So, it is shown that any three consecutive numbers can be divided by three.
Therefore, the given statement is true.
Hence, option (1) is correct.
 
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