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Q.

State whether the given statement is true/false.


The circle x2+y2+2x+4y-20=0 and x2+y2+6x-8y+10=0 are such that the number of common tangents on them is 1.


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a

True

b

False 

answer is B.

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Detailed Solution

Let C1:x2+y2+2x+4y-20=0 and C2:x2+y2+6x-8y+10=0
Center of C1 is (-1, -2) and Center of C2 is (-3, 4).
Radius, r1=-12+-22-(-20)=5
Radius, r2=-32+42-(10)=15
r1+r2=5+15 and C1C2=40=210
r1+r2>C1C2 As a result, circles intersect at two distinct points.
There are two common tangents.
So, the given statement is false.
The correct statement is- The circle x2+y2+2x+4y-20=0 and x2+y2+6x-8y+10=0 are such that the number of common tangents on them is 2.
 
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