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Q.

State whether True or False.


If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.


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a

True

b

False 

answer is A.

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Detailed Solution

Consider a Δ ABC, in which a line DE parallel to BC intersects AB at D and AC at E, i.e., DE ∥ BC
Question ImageJoin BE and CD.
We know that,
Area of a triangle = (1/2) × b × h.
So,
Area of Δ ADE = 1 2 ×AD×EN   Area of Δ BDE = 1 2 ×BD×EN   So, ar(ΔADE) ar(ΔBDE) = 1 2 ×AD×EN 1 2 ×BD×EN   ar(ΔADE) ar(ΔBDE) = 1 2 ×AD×EN 1 2 ×BD×EN ar(ΔADE) ar(ΔBDE) = AD BD ...............(1)  
Similarly, find the area of ΔADE and ΔCDE.
 Area of Δ ADE = 1 2 ×AE×DM   Area of Δ CDE = 1 2 ×AE×DM   So,
ar(ΔADE) ar(ΔCDE) = 1 2 ×AE×DM 1 2 ×EC×DM  Area of ΔADE  Area of ΔCDE = AE EC (2)  
We know the theorem, if two triangles are on the same base and between the same parallels, then they are equal in area.
Since Δ BDE and ΔCDE stand on the same base DE and between the same parallel lines BC and DE,
ar(Δ BDE) = ar(Δ CDE) … (3)
Using eq (1), (2), and (3), we have,
AD DB = AE EC   Hence, it is proved that if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.
So, the correct option is (1).
 
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