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Q.

Statement - I : [Fe(CN)6]3– is weakly paramagnetic while [Fe(CN)6]4– is diamagnetic
Statement - II : Both [Fe(CN)6]3– and [Fe(CN)6]4– involve d2sp3 hybridisation. In [Fe(CN)6]3– singly occupied d-orbital is available but in [Fe(CN)6]4– paired electrons are present

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a

Both statements I and II are correct

b

Statement-I is incorrect and statement-II is correct

c

Both statements I and II are incorrect

d

Statement-I is correct and statement-II is incorrect

answer is A.

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Detailed Solution

Due to the presence of one unpaired electron in the 3d subshell in [Fe(CN)6​]3−, it is weakly paramagnetic. 

On the other hand, [Fe(CN)6​]4− is diamagnetic because all the electrons are paired.

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Statement - I : [Fe(CN)6]3– is weakly paramagnetic while [Fe(CN)6]4– is diamagneticStatement - II : Both [Fe(CN)6]3– and [Fe(CN)6]4– involve d2sp3 hybridisation. In [Fe(CN)6]3– singly occupied d-orbital is available but in [Fe(CN)6]4– paired electrons are present