Statement - I : Ni(CO)₄ complex is tetrahedral in shape
Statement - II : Ni atom undergoes sp³ hybridization in Ni(CO)₄.

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Both statements I and II are correct

Statement-I is incorrect and statement-II is correct

Both statements I and II are incorrect

Statement-I is correct and statement-II is incorrect

answer is A.

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Detailed Solution

Ni oxidation state in Ni(CO)₄ is 0. Its outer electronic configuration becomes 3d⁸ 4s². Electrons of 4s orbitals paired with 3d electrons when CO approaches as CO is a strong ligand. So, the hybridization of Ni(CO)₄ becomes sp³ and has a tetrahedral structure.

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