Statement - I : Reaction of benzaldehyde with formaldehyde in presence of base is crossed Cannizaro’s reaction.
Statement - II : Formaldehyde is always oxidized in this reaction because it is better oxidising agent.

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Both statements I and II are correct

Statement-I is correct and statement-II is incorrect

Statement-I is incorrect and statement-II is correct

Both statements I and II are incorrect

answer is B.

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Detailed Solution

Crossed Cannizzaro reaction between formaldehyde and benzaldehyde-

$\underset{(Benzaldehyde)}{C_{6} H_{5} - CHO} + \underset{(Formaldehyde)}{HCHO} \overset{NaOH}{\to} HCOOH + C_{6} H_{5} - {CH}_{2} - OH$

As there is no electron donating group on formaldehyde, the initial nucleophilic addition of hydroxide ion is faster on formaldehyde due to which formaldehyde oxidises easily and forms formic acid.
Hence the alcohol formed is only benzyl alcohol and not methanol.

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