Statement - I: Aq. ${\mathrm{CuSO}}_4$ on electrolysis using Pt electrodes gives Cu at cathode and ${\mathrm{O}}_2$ at anode

Statement - II : Aq. ${\mathrm{CuSO}}_4$on electrolysis using Cu electrodes gives Cu at cathode and  ${\mathrm{Cu}}^{+2}$ ions at anode

In presence of inert electrode SRP of Cu > SRP of H₂O. Thus Cu⁺² is reduced to Cu at cathode

In presence of attackable electrode metal electrode itself undergoes oxidation at anode, Cu is oxidised to form Cu⁺²