Statement - I :Ce4+ is a good oxidizing agent.Statement - II :Sm2+ is a good reducing agent.

Ce is most stable in +3 state. In +4 state it is most oxidizing because in +4 state it can give an electron to become more stable at +3 state.Whereas in Sm+2, the lanthanides are more stable in +3 state and hence in +2 state it gets oxidized easily (good reducing agent) to get to +3 oxidation state.

Statement - I :Ce4+ is a good oxidizing agent.Statement - II :Sm2+ is a good reducing agent.

Ce is most stable in +3 state. In +4 state it is most oxidizing because in +4 state it can give an electron to become more stable at +3 state.Whereas in Sm+2, the lanthanides are more stable in +3 state and hence in +2 state it gets oxidized easily (good reducing agent) to get to +3 oxidation state.

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Statement - I :Ce⁴⁺ is a good oxidizing agent.
Statement - II :Sm²⁺ is a good reducing agent.

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Both statements I and II are correct

Statement-I is incorrect and statement-II is correct

Both statements I and II are incorrect

Statement-I is correct and statement-II is incorrect

answer is A.

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Detailed Solution

Ce is most stable in +3 state. In +4 state it is most oxidizing because in +4 state it can give an electron to become more stable at +3 state.

Whereas in Sm⁺², the lanthanides are more stable in +3 state and hence in +2 state it gets oxidized easily (good reducing agent) to get to +3 oxidation state.

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