Statement - I :Ce⁴⁺ is a good oxidizing agent.
Statement - II :Sm²⁺ is a good reducing agent.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Both statements I and II are correct

Statement-I is incorrect and statement-II is correct

Both statements I and II are incorrect

Statement-I is correct and statement-II is incorrect

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Ce is most stable in +3 state. In +4 state it is most oxidizing because in +4 state it can give an electron to become more stable at +3 state.

Whereas in Sm⁺², the lanthanides are more stable in +3 state and hence in +2 state it gets oxidized easily (good reducing agent) to get to +3 oxidation state.

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!