Statement - I :If white light is used is YDSE the central bright fringe is white and the fringe closest on either side of the central white fringe is red.
Statement - II :When white light is used in Y.D.S.E for a point ‘P’ for which ${\mathrm{S}}_2\mathrm{P}-{\mathrm{S}}_1\mathrm{P}=\frac{{\mathrm{\lambda }}_{\mathrm{B}}}{2},{\mathrm{\lambda }}_{\mathrm{B}}=$wavelength of blue) the blue component will be absent and fringe will appear red in colour.