Statement - I : The spin only magnetic moment of [MnBr₄]^2- is 5.9 BM.
Statement - II : [MnBr₄]^2- is tetrahedral with sp³ hybridisation of Mn²⁺ having 3d⁵ configuration.

Magnetic moment= $\sqrt{\mathrm{n}\left(\right(\mathrm{n}+2\left)\right)}=5.9\text{ (given) }$
$\therefore$ 35 = n(n+2) or n=5 
Magnetic moment is 5.9 BM means unpaired electrons are 5
Bromine is a type of weak field ligand, so back pairing will not occur.
So, the geometry of the compound is tetrahedral and hybridization is sp³