Statement -1. A carbon atom having an sp hybrid orbitals is less electronegative than carbon atoms possessing $s p^{2}$ or $s p^{3}$ hybridized orbitals.
Statement -2. The percentage of s-character increases then decreases the electronegativity character.
Statement-3. Number of pure and hybrid orbitals in $C H_{4}$ are equal.
Statement-4. All sigma bonds in $C_{2} H_{6}$ are formed due to only one type of overlapping of orbitals.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

(i)&(ii)&(iii) are correct

(i),(ii)and(iv) are incorrect

(ii),(iii) and (iv) are correct

only (iii) incorrect

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

(i),(iii),(iv) statements are incorrect

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test