Statement -1 : A parallel plate capacitor is charged by a battery. The battery is then disconnected. If the distance between the plates is increased, the energy stored in the capacitor will decrease.Statement-2 : Work has to be done to increase the separation between the plates of a charged capacitor

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Statement -1 : A parallel plate capacitor is charged by a battery. The battery is then disconnected. If the distance between the plates is increased, the energy stored in the capacitor will decrease.

Statement-2 : Work has to be done to increase the separation between the plates of a charged capacitor

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Statement-1 is true, Statement-2 is false

Statement-1 is true, Statement-2 is true but Statement-2 is not the correct explation for Statement-1

Statement-1 is false, Statement-2 is true

Statement-1 is true, Statement-2 is true and Statement-2 is the correct explanation for Statement-1

answer is D.

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Detailed Solution

After disconnecting the battery, energy stored in the capacitor is

$U = \frac{1}{2} \frac{Q^{2}}{C}$

We know capacitance is

$C = \frac{A ε_{0}}{d}$

$\Rightarrow U = \frac{1}{2} \frac{Q^{2} d}{{Aε}_{0}}$

Therefore, with increase in the separation, energy stored in the capacitor increases.

Since energy stored in increasing, work is to be done to separate the capacitor plates.

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