Statement -A : The acceleration vector of a particle in uniform circular motion averaged over one cycle is a null vector
Statement -B : The average speed of a particle is either greater or equal to the magnitude of average velocity of the particle over the same interval of the time.

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A only true

Both A & B are false

Both A & B are true

B only true

answer is C.

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Detailed Solution

For a complete cyclic path in uniform circular motion,

$\vec{∆ V} = \vec{0}$

Hence, the acceleration is null vector.

Displacement $\leq$ Path length

Hence, |average velocity| $\leq$ average speed

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