Statement 1  : Between ${\mathrm{SiCl}}_4$and ${\mathrm{CCl}}_4,$ only ${\mathrm{SiCl}}_4$ reacts with water.

Statement 2  :  ${\mathrm{SiCl}}_4$ is ionic and ${\mathrm{CCl}}_4$ is covalent.

${\mathrm{SiCl}}_4$  and other tetra chlorides (except CCl₄) undergoes hydrolysis due to the presence of empty d orbitals in Si that can accommodate lone pairs of oxygen from water. As C has no vacant d orbitals to accommodate electron pairs donated by oxygen atom of water molecules during hydrolysis, therefore CCl₄ cannot undergo hydrolysis.