Statement 1 : Bond order for ${\mathrm{CO}}^{+}$ is more than bond order in CO whereas bond order in ${\mathrm{N}}_2^{+}\mathrm{is}\mathrm{less}\mathrm{than}{\mathrm{N}}_2$ whereas both are isoelectronic.

Statement 2 : Both have same bond order.

The Electronic configuration of 13e^- system  like CO⁺, ${\mathrm{N}}_2^{+}$ is 

For 14e^- system like N₂ , CO is

Bond order of CO⁺ (13e^- ) = $\frac{9-4}{2}=2.5$

Bond order of CO(14e = $\frac{10-4}{2}=3$

So Bond order of CO⁺ is less than CO

Bond order of N₂ = $\frac{10-4}{2}=3$

Bond order of ${\mathrm{N}}_2^{+} = \frac{9-4}{2}=2.5$
So Bond order of ${\mathrm{N}}_2^{+}$ is less than N₂