Statement 1 : Equivalent weight of ${\mathrm{FeC}}_2{\mathrm{O}}_4$ in the reaction,

${\mathrm{FeC}}_2{\mathrm{O}}_4$ + Oxidizing agent $\stackrel{ }{\to }$  ${\mathrm{Fe}}^{3+} + {\mathrm{CO}}_2$ is M/3, where M is molar mass of ${\mathrm{FeC}}_2{\mathrm{O}}_4$

Statement 2 : In the above reaction, total two moles of electrons are given up by 1 mole of ${\mathrm{FeC}}_2{\mathrm{O}}_4$ to the oxidizing agent.