Statement 1 : Equivalent weight of ${FeC}_{2} O_{4}$ in the reaction,
${FeC}_{2} O_{4}$ + Oxidizing agent $\overset{}{\to}$ ${Fe}^{3 +} + {CO}_{2}$ is M/3, where M is molar mass of ${FeC}_{2} O_{4}$
Statement 2 : In the above reaction, total two moles of electrons are given up by 1 mole of ${FeC}_{2} O_{4}$ to the oxidizing agent.

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Statement 1 is false and Statement 2 is true.

Both Statement 1 and Statement 2 are true.

Statement 1 is true and Statement 2 is false.

Both Statement 1 and Statement 2 are false.

answer is B.

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Detailed Solution

$\overset{+ 2}{Fe} {\overset{+ 3}{C}}_{2} {\overset{- 2}{O}}_{4} \to {Fe}^{+ 3} + \overset{+ 4}{C} O_{2} Total change in Oxidation state = 3 E_{{FeC}_{2} O_{4}} = \frac{M}{3}$

(2) ${FeC}_{2} O_{4} \to {Fe}^{+ 3} + 2 {CO}_{2} + 3 e^{-}$

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