Statement 1: 1M aqueous solution of glucose contains 180 g of glucose in 1 kg water.
Statement 2: Solution containing one mole of solute in 1000 g of solvent is called one molal solution.
 

$\text{ Molality (m)=}\frac{ \mathrm{Numberofmolesofsolute} }{ \mathrm{Weightofsolvent}(\mathrm{inkg}) }$
Number of moles of solute = 1
Weight of solvent = 1 kg
Then, molality = l, i.e. one molal glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$.
Molecular weight = 180
Number of moles $=\frac{180}{180}=1$
Weight of water = 1 kg
Hence, molality of the solution in one.