Statement 1: 2-Pentanol and 3-pentanol cannot be distinguished by iodoform test.

Statement 2: 2-Pentanol and 3-pentanol both are secondary alcohols.

 2-Pentanol can be distinguished from 3-pentanol by iodoform test.

$\underset{2-\mathrm{pentanol} (2^{\mathrm{o}}-\mathrm{alcohol})}{{\mathrm{CH}}_3-\underset{\underset{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3} ; \underset{3-\mathrm{pentanol} (2^{\mathrm{o}}-\mathrm{alcohol})}{{\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{\underset{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2-{\mathrm{CH}}_3}$

2-pentanol contains CH₃CHOH group. Therefore, 2- pentanol will give iodoform test and thus form a yellow precipitate of iodoform (CHI₃) whereas the 3-pentanol will not react.