Statement 1: Acetylene on reacting with sodamide gives sodium acetylide and ammonia.

Statement 2: sp-hybridised carbon atoms of acetylene are considerably electronegative.

Acetylene on reaction with sodamide gives sodium acetylide and ammonia.

Here formation of sodium acetylide can be explained by 'sp' hybridization of carbon atom. As we know that an electron in s-orbital is more tightly held than in a p-orbital. ln ‘sp’ hybridization, s-character is 50% as compared to ${\mathrm{sp}}^2$ (33% ) or ${\mathrm{sp}}^3$(25%). So, due to large s-character the carbon atom is quite electronegative and hence Na of ${\mathrm{NaNH}}_2$ can replace ${\mathrm{H}}^{+}$ of C-H bond. Hence statement 1 and statement 2 both are true and statement 2 is the  explanation of statement 1.