Statement 1: ${\mathrm{AlCl}}_3$ forms dimer ${\mathrm{Al}}_2{\mathrm{Cl}}_6$ in gaseous state but it dissolves in ${\mathrm{H}}_2\mathrm{O}$ forming ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+}$ and $3{\mathrm{Cl}}^{-}$ ions.

Statement 2: Aqueous solution of ${\mathrm{AlCl}}_3$ is acidic due to hydrolysis.

Statement 1: In gaseous phase and in non-polar solvent like benzene ${\mathrm{AlCl}}_3$ exists as dimer, ${\mathrm{Al}}_2{\mathrm{Cl}}_6$.  High enthalpy of hydration in water breaks the covalent dimer forming ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+}$ and $3{\mathrm{Cl}}^{-}$.
Statement 2: ${\mathrm{AlCl}}_3+3{\mathrm{H}}_2\mathrm{O}\stackrel{ }{\to }\mathrm{Al}{\left(\mathrm{OH}\right)}_3+3\mathrm{HCl}$