Statement-1 : $[\mathrm{Cr}{\left({\mathrm{NH}}_3\right)}_6{]}^{3+}$ has three unpaired electron in ${t_2}_g$ orbital.

Statement-2 : $[\mathrm{Cr}{\left({\mathrm{NH}}_3\right)}_6{]}^{3+}$ does not show geometrical isomerism.

Statement-1 is false, statement-2 is true.

Statement-1 is true, statement-2 is false.

Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.