Statement-1: Equivalent mass of ${KMnO}_{4}$ is equal to one-third of its molecular mass when it acts as an oxidizing agent in an alkaline medium.
Statement-2: Oxidation number of $Mn$ is $+ 7$ in ${KMnO}_{4}$

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(b) Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-I.

(a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

(d) Statement-1 is False, Statement-2 is True. (e) Statement-I and Statement-2 both are False

answer is B.

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Detailed Solution

${KMnO}_{4}$ as an oxidizer in basic media:

${MnO}_{4}^{-} + {MnOO}_{2} (2 Hs) + O^{2} O^{-} e^{-}$ (gained 3 electrons)

Equivalent weight of ${KMnO}_{4}$ $= \frac{158.04}{3} = 52.68$ grams/equivalent

Oxidation number of $Mn$ is $+ 7$ in ${KMnO}_{4}$ .

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