Statement 1 : In ${\mathrm{SF}}_6$ molecule F-S-F bond angle is 90°.
Statement 2:  ${\mathrm{SF}}_6$ molecule has octahedral geometry with ${\mathrm{sp}}^3{\mathrm{d}}^2$ - hybridization.

Formation of ${\mathrm{SF}}_6\left({\mathrm{sp}}^3{\mathrm{d}}^2\text{-hybridisation }\right)$
In ${\mathrm{SF}}_6$ the central sulphur atom has the ground state outer electronic configuration $3{\mathrm{s}}^{2}3{\mathrm{p}}^4$. In the excited state the available six orbitals, i.e. one s, three p and two d are singly occupied by electrons.
These orbitals hybridize to form six new ${\mathrm{sp}}^3{\mathrm{d}}^2$- hybrid orbitals, which are projected towards the six corners of a regular octahedron in ${\mathrm{SF}}_6$.