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Q.

Statement 1: let  f:[0,3][1,13]  is defined by  f(x)=x2+x+1, then inverse is  f1(x)=1+4x32

Statement 2: many one function is not invertible.

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a

Statement 1 incorrect  and statement 2 is correct

b

Both statement 1 and statement 2 are correct

c

Statement 1 is correct and statement 2 is incorrect.

d

Statement 1 is incorrect and statement 2 is incorrect.

answer is B.

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Detailed Solution

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We have  f(x)=x2+x+1,  f1(x)=2x+1>0  in [0,3]
f(x)  is one-one and its range is  [f(0),f(3)]=[1,13]
      Range =codomain, hence it is invertible
f1(x)1+4x32

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