Statement 1: Methanol is stronger acid than water.

Statement 2: AII alcohols are stronger acid than water.

CH₃OH is stronger acid than water and rest all alcohols are weaker acids.

$\underset{\mathrm{Base}}{\mathrm{R}-{\mathrm{O}}^{-}}+\underset{\mathrm{Acid}}{\mathrm{H}-\mathrm{O}-\mathrm{H} }\to \underset{\mathrm{conjugate} \mathrm{acid}}{ \mathrm{R}-\mathrm{OH}} + \underset{\mathrm{conjugate} \mathrm{base}}{{\mathrm{OH}}^{-}}$

This reaction shows that water is a better proton donor(stronger acid) than alcohol.