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Q.

Statement 1 :  sin1TanTan1x+Tan11x=π2 has no non-zero integral solution
Statement 2 :  Tan18°=251055
 

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a

Statement-1 is true, statement-2 is true; statement-2 is a correct explination for statement-1

b

Statement-1 is true, statement-2 is true; statement-2 is not a correct explination for statement-1

c

Statement-1 is true, statement-2 is false

d

Statement-1 is false, statement-2 is true.

answer is D.

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Detailed Solution

Sin1TanTan1x+Tan11x=π2

Sin1TanTan1x+1x1x1x=π2

TanTan111x+x2=sinπ2

11x+x2=1x2x+1=1x=0,1

 statement-1 is not true
Clearly statement-2 is true.
TAn18°=sin18°cos18°=5110+25

(Rationalising denominator)

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Statement 1 :  sin−1TanTan−1x+Tan−11−x=π2 has no non-zero integral solutionStatement 2 :  Tan18°=25−1055