Statement-1: The crystal structure of ${\mathrm{NaHCO}}_3$ and ${\mathrm{KHCO}}_3$, both show intermolecular hydrogen bonding but are different.
Statement-2: In ${\mathrm{NaHCO}}_3$ the ${\mathrm{HCO}}_3^{-}$ ions are linked together through intermolecular hydrogen n bonds into an infinite chain, while in ${\mathrm{KHCO}}_3$, ${\mathrm{HCO}}_3^{-}$ ions form dimerie anions through intermolecular hydrogen bonds.

${\mathrm{Na}}^{+}{\mathrm{HCO}}_3^{-}$ has extensive hydrogen bonding and thus is the only insoluble bicarbonate.
Both the crystal structures of ${\mathrm{NaHCO}}_3$ and ${\mathrm{KHCO}}_3$ exhibit intermolecular hydrogen bonds, yet they are distinct from one another. while in ${\mathrm{KHCO}}_3$3, ${\mathrm{HCO}}_3^{-}$ ions form dimeric anions by intermolecular hydrogen bonds, the ${\mathrm{HCO}}_3^{-}$ ions in ${\mathrm{NaHCO}}_3$ are joined together through intermolecular hydrogen n bonds to create an endless chain.
Hence, correct option is A