Statement-1: The highest $Mn$ fluoride is ${MnF}_{4}$ whereas the highest oxide is ${Mn}_{2} O_{7}$ .
Statement-2: The ability of oxygen to stabilise high oxidation states exceeds that of fluorine.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Statement-1 is False, Statement-2 is True.

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

Stat.ement-1 is True, Statement-2 is True; Statemen~2 is a correct explanation for Statement-1.

Statement--1 is True, Statement-2 is False.

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Fluoride cannot stabilise the high oxidation states as effectively as oxygen can. ${MnF}_{4}$ is the highest $Mn$ fluoride, whereas ${Mn}_{2} O_{7}$ is the highest $Mn$ oxide.
Fluorine is unable to form multiple bonds with metals, whereas oxygen is capable of doing so. As a result, oxygen has a greater capacity than fluorine to stabilise higher oxidation states.

Watch 3-min video & get full concept clarity