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Statement 1: The least and greatest distance of the point P(10,7) from the circle $x^{2} + y^{2} - 4 x - 2 y - 20 = 0$ are 5 and 15 units respectively.
Statement 2: A point $(x_{1}, y_{1})$ lies outside a circle $s = x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ if $s_{1} > 0$ where $s_{1} = x_{1}^{2} + y_{1}^{2} + 2 g x_{1} + 2 f y_{1} + c .$

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Statement I is True, Statement 2 is True; Statement 2 is correct explanation for Statement I

Statement 1 is True; Statement 2 is False

Statement 1 is False; Statement 2 is True

Statement 1 is True, Statement 2 is True; Statement 2 NOT a correct explanation for Statement 1

answer is B.

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Detailed Solution

Centre of the circle (2,1); $r = \sqrt{25} = 5$ distance of (10,7) from (2,1) is 10 units hence required distances are 5,15 respectively.

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