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Statement-1: The only circle having radius $10$ and a diameter along the line $2 x + y = 5$ is $x 2 + y 2 − 6 x + 2 y = 0$
Statement-2: $2 x + y = 5$ is normal to the circle $x 2 + y 2 − 6 x + 2 y = 0$

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Statement-1 and Statement-2 both are correct and Statement-2 is NOT the correct explanation for Statement-1

Statement-1 and Statement-2 both are correct and Statement-2 is the correct explanation for Statement-1

Statement-1 is false and Statement-2 is true

Statement-1 is true and Statement-2 is false

answer is D.

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Detailed Solution

several circles can be drawn with different radii whose centre lies on the line 2x+y =5. There fore statement I is false

centre of the circle $x 2 + y 2 − 6 x + 2 y = 0$ (3,-1) lies on 2x+y=5 There fore statement I is true

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